Epsilon --- Introduction ---

This is an exercise on the definition of continuity :

A function f  is continuous on a point x0, if:

For all varepsilon> 0, there exists a delta> 0, such that |x-x0| le delta implies |f (x)-f (x0)| le varepsilon.

Given a concret function (who is continuous), a x0 and a varepsilon> 0, you have to find a delta> 0 which verifies the above condition. And you will be noted according to this delta: more it is close to the best possible value, better will be your note.

Choose the type of online help you want:

Other exercises on:
The most recent version

This page is not in its usual appearance because WIMS is unable to recognize your web browser.
In order to access WIMS services, you need a browser supporting forms. In order to test the browser you are using, please type the word wims here: and press ``Enter''.

Please take note that WIMS pages are interactively generated; they are not ordinary HTML files. They must be used interactively ONLINE. It is useless for you to gather them through a robot program.